Armor

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(Hardened)
(Stealth Armor)
 
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== Currently Available Armor Types ==
== Currently Available Armor Types ==
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'''<div id="Ferro Fibrous">Ferro Fibrous</div>'''
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===<div id="Ferro Fibrous">Ferro Fibrous</div>===
*Ferro Fibrous armor is the standard armor use to protect a mech. It weighs less than Reactive and Reflective armor, but takes up less space.
*Ferro Fibrous armor is the standard armor use to protect a mech. It weighs less than Reactive and Reflective armor, but takes up less space.
**Ferro Fibrous provides 30 points of protection per ton and is equally resistant to all damage.
**Ferro Fibrous provides 30 points of protection per ton and is equally resistant to all damage.
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'''<div id="Reactive">Reactive</div>'''
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===<div id="Reactive">Reactive</div>===
*Reactive Armor weighs more than Ferro Fibrous armor, but provides more protection against [[:Category:Ballistic Weapons|Ballistic Type]] weapons.
*Reactive Armor weighs more than Ferro Fibrous armor, but provides more protection against [[:Category:Ballistic Weapons|Ballistic Type]] weapons.
**Reactive armor provides 20 points of protection per ton, but damage from ballistic weapons is reduced by half.
**Reactive armor provides 20 points of protection per ton, but damage from ballistic weapons is reduced by half.
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'''<div id="Reflective">Reflective</div>'''
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===<div id="Reflective">Reflective</div>===
*Reflective Armor weighs more than Ferro Fibrous armor, but provides more protection against [[:Category:Energy Weapons|Energy Type]] weapons.
*Reflective Armor weighs more than Ferro Fibrous armor, but provides more protection against [[:Category:Energy Weapons|Energy Type]] weapons.
**Reflective armor provides 20 points of protection per ton, but damage from energy weapons is reduced by half.
**Reflective armor provides 20 points of protection per ton, but damage from energy weapons is reduced by half.
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#(15 * .667) - (18.31/10 - 0.0) = (10) - (1.83) = 8.17
#(15 * .667) - (18.31/10 - 0.0) = (10) - (1.83) = 8.17
#(15 * .667) - (10.14/10 - 0.0) = (10) - (1.05) = 9.97
#(15 * .667) - (10.14/10 - 0.0) = (10) - (1.05) = 9.97
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#(15 * .667) - (01.15/10 - 0.0) = (10) - (0.12) = 9.88 (CT is destroyed)
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#(15 * .667) - (01.15/10 - 0.0) = (10) - (0.12) = 9.88 (CT armor is destroyed)
*Notice the less armor remains, the less effective Damage Reduction is.
*Notice the less armor remains, the less effective Damage Reduction is.
*Any weapon that does less than 1.5x the Damage Reduction number will do no damage to hardened armor. (Such as [[Machine Gun]]s or lower power lasers)
*Any weapon that does less than 1.5x the Damage Reduction number will do no damage to hardened armor. (Such as [[Machine Gun]]s or lower power lasers)
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#(15 * 1.0) - (37.94/30 - 1.0) = (15) - (0.26) = 14.74
#(15 * 1.0) - (37.94/30 - 1.0) = (15) - (0.26) = 14.74
#(15 * 1.0) - (23.20/30 - 1.0) = (15) - (-.23) = 15.23
#(15 * 1.0) - (23.20/30 - 1.0) = (15) - (-.23) = 15.23
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#(15 * 1.0) - (07.97/30 - 1.0) = (15) - (-.73) = 15.73 (CT is destroyed)
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#(15 * 1.0) - (07.97/30 - 1.0) = (15) - (-.73) = 15.73 (CT armor is destroyed)
*It would also take 5 hits to destroy an equal tonnage of FF using the current armor system.
*It would also take 5 hits to destroy an equal tonnage of FF using the current armor system.
**The difference between the two systems after four hits is 1.97 (6 points with the current system, 7.97 with the future one).
**The difference between the two systems after four hits is 1.97 (6 points with the current system, 7.97 with the future one).
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#(15 * 0.75) - (29.59/20 - 0.5) = (11.25) - (0.98) = 10.27
#(15 * 0.75) - (29.59/20 - 0.5) = (11.25) - (0.98) = 10.27
#(15 * 0.75) - (19.32/20 - 0.5) = (11.25) - (0.47) = 10.78
#(15 * 0.75) - (19.32/20 - 0.5) = (11.25) - (0.47) = 10.78
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#(15 * 0.75) - (08.54/20 - 0.5) = (11.25) - (-.07) = 11.32 (CT is destroyed)
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#(15 * 0.75) - (08.54/20 - 0.5) = (11.25) - (-.07) = 11.32 (CT armor is destroyed)
*The CT took 7 shots compared to 5 with full ferro fibrous. However, 50% more tonnage dedicated to armor was required.
*The CT took 7 shots compared to 5 with full ferro fibrous. However, 50% more tonnage dedicated to armor was required.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 4 hits would destroy the CT.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 4 hits would destroy the CT.
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#(15 * 1.0) - (40.99/20 - 0.5) = (15) - (1.54) = 13.46
#(15 * 1.0) - (40.99/20 - 0.5) = (15) - (1.54) = 13.46
#(15 * 1.0) - (27.53/20 - 0.5) = (15) - (0.88) = 14.12
#(15 * 1.0) - (27.53/20 - 0.5) = (15) - (0.88) = 14.12
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#(15 * 1.0) - (13.41/20 - 0.5) = (15) - (0.17) = 14.83 (CT is destroyed)
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#(15 * 1.0) - (13.41/20 - 0.5) = (15) - (0.17) = 14.83 (CT armor is destroyed)
*When compared to ferro fibrous, 3.3 tons of reactive armor provides the same protection against missiles and energy weapons. However, to get this same protection, 50% more tonnage must be allocated to armor.
*When compared to ferro fibrous, 3.3 tons of reactive armor provides the same protection against missiles and energy weapons. However, to get this same protection, 50% more tonnage must be allocated to armor.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 4 hits would destroy the CT.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 4 hits would destroy the CT.
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#(15 * 0.5) - (21.12/20 - 0.5) = (7.5) - (0.53) = 6.97
#(15 * 0.5) - (21.12/20 - 0.5) = (7.5) - (0.53) = 6.97
#(15 * 0.5) - (14.15/20 - 0.5) = (7.5) - (0.21) = 7.29
#(15 * 0.5) - (14.15/20 - 0.5) = (7.5) - (0.21) = 7.29
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#(15 * 0.5) - (06.86/20 - 0.5) = (7.5) - (-.16) = 7.66 (CT is destroyed)
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#(15 * 0.5) - (06.86/20 - 0.5) = (7.5) - (-.16) = 7.66 (CT armor is destroyed)
*When compared to ferro fibrous, the amount of damage taken is more than doubled thanks to damage reduction.
*When compared to ferro fibrous, the amount of damage taken is more than doubled thanks to damage reduction.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 7 hits would destroy the CT.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 7 hits would destroy the CT.
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#(15 * 1.15) - (48.75/0 - 0) = (17.25) - (0) = 17.25
#(15 * 1.15) - (48.75/0 - 0) = (17.25) - (0) = 17.25
#(15 * 1.15) - (31.50/0 - 0) = (17.25) - (0) = 17.25
#(15 * 1.15) - (31.50/0 - 0) = (17.25) - (0) = 17.25
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#(15 * 1.15) - (14.25/0 - 0) = (17.25) - (0) = 17.25 (CT is destroyed)
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#(15 * 1.15) - (14.25/0 - 0) = (17.25) - (0) = 17.25 (CT armor is destroyed)
*Stealth armor will reduced the enemy's radar effectiveness by 10%, but only if every section of your mech is equipped with stealth armor.
*Stealth armor will reduced the enemy's radar effectiveness by 10%, but only if every section of your mech is equipped with stealth armor.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 3 hits would destroy the CT.
*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 3 hits would destroy the CT.
Note that once these future armor types are released, different armor types can be used on each section. For example, you can use full stealth armor on you CT, full ferro fibrous on your torso's and arms, and full reflective on your legs. This can be extremely useful if your CT also houses some of your heaviest weapons. Only with stealth armor is it important to equip each section with the same armor type.
Note that once these future armor types are released, different armor types can be used on each section. For example, you can use full stealth armor on you CT, full ferro fibrous on your torso's and arms, and full reflective on your legs. This can be extremely useful if your CT also houses some of your heaviest weapons. Only with stealth armor is it important to equip each section with the same armor type.

Latest revision as of 04:15, 5 June 2011

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