Armor

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(Future Armor Types)
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*Hardened Armor weighs more than Ferro Fibrous armor, but provides more protection against all weapons.
*Hardened Armor weighs more than Ferro Fibrous armor, but provides more protection against all weapons.
**Hardened Armor provides 10 points of protection per ton, but damage from all weapons is reduced by 1/3.
**Hardened Armor provides 10 points of protection per ton, but damage from all weapons is reduced by 1/3.
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=== Future armor attributes ===
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====Here are the armor types:====
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# Ferro Fibrous
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# Standard (new)
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# Reflective
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# Reactive
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# Stealth (new)
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# Hardened (new)
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==== Damage Resistance%:====
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*Rules:
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#Reflective reduces energy attacks by 50%
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#Reactive reduces ballstic attacks by 50%
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#Hardened armor reduces all attacks by 33%
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#Standard armor reduces all attacks by 25%
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#Stealth armor amplifies all attaks by 15%
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#FF is even up
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====Armor Points per Ton====
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#FF 30 points per ton (PPT)
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#Reactive 20 PPT
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#Reflective 20 PPT
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#Standard 20 PPT
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#Stealth 20 PPT
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#Hardened 10 PPT
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====Damage Reduction====
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In addition, armor types have different DR (damage reduction). DR reduces an attack by a certain amount.
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First of all, there is a DR offset. This works against the defender. If DR is computed to be less than zero it is treated as zero.
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*FF has offset of 1.0
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*Reactive and reflective, offset 0.5.
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*Standard has DR of offset 0.5
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*Hardened a DR of offset 0.0
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*Stealth has offset 0.0. In fact, it always has a DR of zero.
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Now each armor type has a certain amount of points of armor for DR. It is equal to points per ton. You subtract the offset to get the real DR value.
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*For FF 30 points of armor
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*Reactive and Reflective is 20
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*Standard and Stealth is 20
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*Hardened is 10
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====Formulas for Armor Types====
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The final result is:<br>
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(attack strength*damage resistance) - (armor points/damage reduction - offset) = damage taken
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Just in case I lost you, here is an in game example using a Mad Cat and an ER PPC:
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*The Mad Cat can carry a total of 66 points of any given type of armor on its center torso
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*An ER PPC does 15 points of damage
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**Here is how many hits it would take to completely remove all armor from the CT with each armor type:
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Hardened (6.6 Tons of armor):
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#(15 * .667) - (66.00/10 - 0.0) = (10) - (6.60) = 3.4
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#(15 * .667) - (62.60/10 - 0.0) = (10) - (6.26) = 3.74
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#(15 * .667) - (58.86/10 - 0.0) = (10) - (5.89) = 4.11
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#(15 * .667) - (54.75/10 - 0.0) = (10) - (4.53) = 5.47
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#(15 * .667) - (49.28/10 - 0.0) = (10) - (4.93) = 5.07
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#(15 * .667) - (44.21/10 - 0.0) = (10) - (4.42) = 5.57
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#(15 * .667) - (38.63/10 - 0.0) = (10) - (3.86) = 6.14
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#(15 * .667) - (32.49/10 - 0.0) = (10) - (3.25) = 6.75
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#(15 * .667) - (25.74/10 - 0.0) = (10) - (2.57) = 7.43
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#(15 * .667) - (18.31/10 - 0.0) = (10) - (1.83) = 8.17
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#(15 * .667) - (10.14/10 - 0.0) = (10) - (1.05) = 9.97
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#(15 * .667) - (01.15/10 - 0.0) = (10) - (0.12) = 9.88 (CT is destroyed)
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*Notice the less armor remains, the less effective Damage Reduction is.
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*Any weapon that does less than 2x the Damage Reduction number will do no damage to hardened armor. (Such as [[Machine Gun]]s or lower power lasers)
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*Hardened armor is more effective against low damage weapons
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*Weapons with armor piercing will ignore Damage Reduction completely
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*Though it took 12 ER PPC hits to destroy the CT, it required 3X as much tonnage to be dedicated to the CT as a CT with full ferro fibrous armor.
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*Assuming you maxed out your Mad Cat's armor with hardened armor, the total armor tonnage would be 43.2 tons.
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**If you stripped all weapons and equipment, you would only be left with 15.3 free tons
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**If you allocated the same tonnage to hardened armor as you could full reactive, reflective, standard, or stealth, the CT would take 5 hits to destroy the CT
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**If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 3 hits would destroy the CT
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Ferro Fibrous Armor (2.2 Tons of armor):
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#(15 * 1.0) - (66.00/30 - 1.0) = (15) - (1.20) = 13.8
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#(15 * 1.0) - (52.20/30 - 1.0) = (15) - (0.74) = 14.26
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#(15 * 1.0) - (37.94/30 - 1.0) = (15) - (0.26) = 14.74
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#(15 * 1.0) - (23.20/30 - 1.0) = (15) - (-.23) = 15.23
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#(15 * 1.0) - (07.97/30 - 1.0) = (15) - (-.73) = 15.73 (CT is destroyed)
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*It would also take 5 hits to destroy an equal tonnage of FF using the current armor system.
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**The difference between the two systems after four hits is 1.97 (6 points with the current system, 7.97 with the future one).
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Against standard (3.3 tons of armor):
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#(15 * 0.75) - (66.00/20 - 0.5) = (11.25) - (2.80) =  8.45
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#(15 * 0.75) - (57.55/20 - 0.5) = (11.25) - (2.38) =  8.87
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#(15 * 0.75) - (48.68/20 - 0.5) = (11.25) - (1.93) =  9.31
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#(15 * 0.75) - (39.37/20 - 0.5) = (11.25) - (1.47) =  9.78
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#(15 * 0.75) - (29.59/20 - 0.5) = (11.25) - (0.98) = 10.27
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#(15 * 0.75) - (19.32/20 - 0.5) = (11.25) - (0.47) = 10.78
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#(15 * 0.75) - (08.54/20 - 0.5) = (11.25) - (-.07) = 11.32 (CT is destroyed)
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*The CT took 7 shots compared to 5 with full ferro fibrous. However, 50% more tonnage dedicated to armor was required.
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*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 4 hits would destroy the CT.
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Against Reactive (3.3 tons of armor):
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#(15 * 1.0) - (66.00/20 - 0.5) = (15) - (2.80) = 12.20
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#(15 * 1.0) - (53.80/20 - 0.5) = (15) - (2.19) = 12.81
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#(15 * 1.0) - (40.99/20 - 0.5) = (15) - (1.54) = 13.46
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#(15 * 1.0) - (27.53/20 - 0.5) = (15) - (0.88) = 14.12
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#(15 * 1.0) - (13.41/20 - 0.5) = (15) - (0.17) = 14.83 (CT is destroyed)
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*When compared to ferro fibrous, 3.3 tons of reactive armor provides the same protection against missiles and energy weapons. However, to get this same protection, 50% more tonnage must be allocated to armor.
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*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 4 hits would destroy the CT.
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Against Reflective(3.3 tons of armor):
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#(15 * 0.5) - (66.00/20 - 0.5) = (7.5) - (2.80) = 4.70
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#(15 * 0.5) - (61.30/20 - 0.5) = (7.5) - (2.57) = 4.93
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#(15 * 0.5) - (56.37/20 - 0.5) = (7.5) - (2.31) = 5.19
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#(15 * 0.5) - (51.18/20 - 0.5) = (7.5) - (2.06) = 5.44
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#(15 * 0.5) - (45.74/20 - 0.5) = (7.5) - (1.79) = 5.71
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#(15 * 0.5) - (40.03/20 - 0.5) = (7.5) - (1.50) = 6.00
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#(15 * 0.5) - (34.03/20 - 0.5) = (7.5) - (1.20) = 6.30
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#(15 * 0.5) - (27.73/20 - 0.5) = (7.5) - (0.89) = 6.61
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#(15 * 0.5) - (21.12/20 - 0.5) = (7.5) - (0.53) = 6.97
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#(15 * 0.5) - (14.15/20 - 0.5) = (7.5) - (0.21) = 7.29
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#(15 * 0.5) - (06.86/20 - 0.5) = (7.5) - (-.16) = 7.66 (CT is destroyed)
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*When compared to ferro fibrous, the amount of damage taken is more than doubled thanks to damage reduction.
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*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 7 hits would destroy the CT.
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*Shares the same disadvantages against missile and ballistic weapons as reactive armor does against missile and energy weapons.
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Against Stealth(3.3 tons of armor):
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#(15 * 1.15) - (66.00/0 - 0) = (17.25) - (0) = 17.25
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#(15 * 1.15) - (48.75/0 - 0) = (17.25) - (0) = 17.25
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#(15 * 1.15) - (31.50/0 - 0) = (17.25) - (0) = 17.25
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#(15 * 1.15) - (14.25/0 - 0) = (17.25) - (0) = 17.25 (CT is destroyed)
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*Stealth armor will reduced the enemy's radar effectiveness by 10%, but only if every section of your mech is equipped with stealth armor.
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*If you allocated the same tonnage to hardened armor as you could full ferro fibrous, 3 hits would destroy the CT.
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Note that once these future armor types are released, different armor types can be used on each section. For example, you can use full stealth armor on you CT, full ferro fibrous on your torso's and arms, and full reflective on your legs. This can be extremely useful if your CT also houses some of your heaviest weapons. Only with stealth armor is it important to equip each section with the same armor type.

Revision as of 06:22, 9 December 2010

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